Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:55Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
191K
∇²z = 0
det| 9 4 ; 1 10 | = 86
153K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 4 ; 5 5 | = 0
473K
8t² + 2t + 3 = 0
det| 3 6 ; 0 4 | = 12
188K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2