Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 22:04Z
N₂ + 3H₂ ⇌ 2NH₃
3β² + 9β + 4 = 0
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
100K
12t² + 5t + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
375K
det| 9 4 ; 1 10 | = 86
139K
10n² + 8n + 7 = 0
det| 3 3 ; 4 4 | = 0
412K
∑_{k=1}^{n} k = n(n+1)/2
28K