Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:02Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
276K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 3 1 ; 7 4 | = 5
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det| 12 1 ; 1 13 | = 155
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-θ²) dθ = √π / 2