Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:22Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
75K
det| 5 9 ; 7 6 | = -33
479K
8β² + 2β + 0 = 0
det| 7 4 ; 4 8 | = 40
276K
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
det| 4 8 ; 3 5 | = -4
153K
det| 12 1 ; 1 13 | = 155