Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 4 4 ; 5 5 | = 0
479K
11n² + 1n + 0 = 0
det| 1 1 ; 5 2 | = -3
276K
det| 5 6 ; 7 6 | = -12
129K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
4y² + 8y + 1 = 0
det| 10 9 ; 0 11 | = 110
1K
det| 11 7 ; 4 12 | = 104
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
416K