Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:52Z
det| 3 3 ; 5 4 | = -3
∫₀^∞ e^(-φ²) dφ = √π / 2
75K
det| 7 4 ; 4 8 | = 40
479K
∇²β = 0
e^{i\pi} + 1 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
153K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
E = mc²
det| 3 7 ; 2 4 | = -2
det| 8 5 ; 1 9 | = 67
∂t/∂β = 2t