Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:27Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
75K
3β² + 6β + 2 = 0
F = ma
∑_{k=1}^{n} k = n(n+1)/2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 10 9 ; 0 11 | = 110
1K
1x² + 5x + 7 = 0
det| 3 6 ; 0 4 | = 12
473K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
338K
∇²ψ = 0