Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:31Z
det| 3 3 ; 5 4 | = -3
∇²β = 0
det| 10 9 ; 0 11 | = 110
276K
∫₀^∞ e^(-φ²) dφ = √π / 2
129K
e^{i\pi} + 1 = 0
E = mc²
∫₀^∞ e^(-t²) dt = √π / 2
1K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
E = mc²