Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:40Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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8β² + 2β + 0 = 0
det| 11 9 ; 0 12 | = 132
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∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
338K