Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 15:35Z
\lim_{y\to 0} \frac{\sin y}{y} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 8 8 ; 0 9 | = 72
\lim_{t\to 0} \frac{\sin t}{t} = 1
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λ = h/p
det| 4 8 ; 3 5 | = -4
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-t²) dt = √π / 2
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