Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:35Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
3β² + 6β + 2 = 0
det| 10 9 ; 0 11 | = 110
276K
det| 7 4 ; 4 8 | = 40
129K
F = ma
det| 6 6 ; 3 7 | = 24
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}