Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:24Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
E = mc²
det| 7 2 ; 7 8 | = 42
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
176K
∫₀^∞ e^(-ψ²) dψ = √π / 2
319K
det| 12 1 ; 4 13 | = 152
359K
det| 7 4 ; 4 8 | = 40
233K