Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:05Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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12β² + 9β + 3 = 0
det| 4 8 ; 3 5 | = -4
129K
∂z/∂n = 8z
∑_{k=1}^{n} k = n(n+1)/2
191K
e^{i\pi} + 1 = 0
det| 10 2 ; 1 11 | = 108
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
338K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
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∫₀^∞ e^(-ψ²) dψ = √π / 2