Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:47Z
ω = 2πf
det| 4 6 ; 4 5 | = -4
75K
∑_{k=1}^{n} k = n(n+1)/2
479K
7x² + 6x + 1 = 0
det| 3 1 ; 7 4 | = 5
276K
det| 11 9 ; 5 12 | = 87
129K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 9 4 ; 1 10 | = 86
191K
∫₀^∞ e^(-t²) dt = √π / 2
390K
5β² + 9β + 2 = 0
e^{i\pi} + 1 = 0
∇²β = 0
E = mc²
10z² + 3z + 2 = 0
det| 4 8 ; 6 5 | = -28