Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:04Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
75K
det| 7 9 ; 1 8 | = 47
479K
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
191K
∫₀^∞ e^(-φ²) dφ = √π / 2
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1