Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 08:14Z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
352K
2H₂ + O₂ → 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
375K
7ψ² + 9ψ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
89K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
63K
det| 7 4 ; 4 8 | = 40
39K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
176K
det| 5 3 ; 7 6 | = 9
296K