Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:49Z
det| 4 5 ; 4 5 | = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
479K
N₂ + 3H₂ ⇌ 2NH₃
det| 7 4 ; 4 8 | = 40
276K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = G m₁m₂ / r²
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
473K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
e^{i\pi} + 1 = 0
F = G m₁m₂ / r²
F = ma