Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:37Z
∑_{k=1}^{n} k = n(n+1)/2
det| 11 5 ; 0 12 | = 132
479K
3β² + 6β + 2 = 0
det| 1 4 ; 3 2 | = -10
276K
F = ma
det| 7 4 ; 4 8 | = 40
191K
det| 10 4 ; 1 11 | = 106
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
1x² + 5x + 7 = 0