Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:55Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
75K
det| 3 1 ; 7 4 | = 5
479K
3β² + 6β + 2 = 0
F = ma
det| 3 7 ; 2 4 | = -2
191K
det| 4 6 ; 4 5 | = -4
390K
det| 9 4 ; 1 10 | = 86
153K
∫₀^∞ e^(-t²) dt = √π / 2
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