Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:02Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
276K
\lim_{β\to 0} \frac{\sin β}{β} = 1
129K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
191K
\lim_{r\to 0} \frac{\sin r}{r} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
338K