Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 19:16Z
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
352K
4r² + 2r + 4 = 0
∫₀^∞ e^(-x²) dx = √π / 2
143K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 5 3 ; 3 6 | = 21
det| 11 5 ; 0 12 | = 132
63K
det| 1 4 ; 3 2 | = -10
361K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
8z² + 1z + 0 = 0
F = ma
∫₀^∞ e^(-ω²) dω = √π / 2
5γ² + 6γ + 3 = 0