Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:02Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
479K
8β² + 2β + 0 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
276K
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 12 1 ; 1 13 | = 155
∫₀^∞ e^(-φ²) dφ = √π / 2
473K
N₂ + 3H₂ ⇌ 2NH₃
det| 5 5 ; 2 6 | = 20
e^{i\pi} + 1 = 0