Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:42Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 6 6 ; 3 7 | = 24
191K
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
8t² + 2t + 3 = 0
det| 3 7 ; 2 4 | = -2
188K
det| 4 6 ; 4 5 | = -4
416K
F = ma