Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:27Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
det| 11 9 ; 0 12 | = 132
129K
F = ma
det| 3 7 ; 2 4 | = -2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
188K