Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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3β² + 6β + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 9 4 ; 1 10 | = 86
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F = ma
det| 5 9 ; 0 6 | = 30
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det| 3 6 ; 0 4 | = 12
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