Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:41Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
det| 7 2 ; 7 8 | = 42
129K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 10 4 ; 1 11 | = 106
473K
det| 7 4 ; 4 8 | = 40
188K