Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:38Z
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
276K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
129K
F = ma
det| 7 6 ; 1 8 | = 50
191K
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 3 ; 7 6 | = 9
473K