Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:32Z
∂r/∂φ = 2r
\binom{n}{k} = \frac{n!}{k!(n-k)!}
326K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
366K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
359K
d/dy [y^11] = 11y^10
233K