Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:57Z
ω = 2πf
det| 3 1 ; 7 4 | = 5
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7r² + 8r + 6 = 0
∫₀^∞ e^(-n²) dn = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 3 11 | = 83
det| 4 4 ; 5 5 | = 0
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∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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