Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:36Z
d/dz [z^3] = 3z^2
∑_{k=1}^{n} k = n(n+1)/2
479K
6φ² + 8φ + 0 = 0
det| 9 4 ; 1 10 | = 86
129K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 10 8 ; 7 11 | = 54
det| 5 9 ; 7 6 | = -33
153K
det| 5 6 ; 2 6 | = 18
det| 3 6 ; 0 4 | = 12
338K