Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:11Z
11t² + 7t + 4 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 3 ; 2 6 | = 24
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
d/dy [y^11] = 11y^10
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