Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:22Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 9 4 ; 1 10 | = 86
153K
det| 12 1 ; 1 13 | = 155
∫₀^∞ e^(-t²) dt = √π / 2
473K
N₂ + 3H₂ ⇌ 2NH₃