Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:24Z
11t² + 7t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
198K
E = mc²
∫₀^∞ e^(-t²) dt = √π / 2
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 3 ; 2 6 | = 24
366K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
CH₄ + 2O₂ → CO₂ + 2H₂O
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
263K
d/dy [y^11] = 11y^10
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