Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:46Z
ω = 2πf
det| 1 4 ; 0 2 | = 2
198K
7r² + 8r + 6 = 0
det| 7 4 ; 4 8 | = 40
63K
∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 3 11 | = 83
det| 5 9 ; 7 6 | = -33
176K
2ψ² + 6ψ + 0 = 0
det| 5 2 ; 3 6 | = 24
263K
ω = 2πf
6θ² + 3θ + 6 = 0