Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
479K
3β² + 6β + 2 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
129K
F = ma
det| 12 1 ; 4 13 | = 152
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K