Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 21:47Z
d/dx [x^11] = 11x^10
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
234K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
278K
4r² + 1r + 1 = 0
det| 7 6 ; 1 8 | = 50
392K
∂φ/∂θ = 6φ
det| 7 4 ; 4 8 | = 40
330K
det| 2 1 ; 7 3 | = -1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
375K
\frac{10}{1} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
412K
∑_{k=1}^{n} k = n(n+1)/2
223K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0