Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 11:02Z
d/dβ [β^10] = 10β^9
det| 2 5 ; 1 3 | = 1
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
89K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
5t² + 1t + 5 = 0
det| 4 6 ; 4 5 | = -4
176K
iħ ∂ψ/∂t = Ĥψ
N₂ + 3H₂ ⇌ 2NH₃