Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:27Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
3β² + 6β + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
276K
det| 7 4 ; 4 8 | = 40
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 3 ; 2 6 | = 24
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∑_{k=1}^{n} k = n(n+1)/2
338K