Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:02Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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8β² + 2β + 0 = 0
det| 7 2 ; 7 8 | = 42
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∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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det| 10 7 ; 3 11 | = 89
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det| 7 4 ; 4 8 | = 40
188K