Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 6 ; 6 9 | = 36
75K
11n² + 1n + 0 = 0
det| 5 9 ; 0 6 | = 30
276K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 7 4 ; 4 8 | = 40
390K
4y² + 8y + 1 = 0
det| 12 1 ; 4 13 | = 152
1K
det| 1 1 ; 5 2 | = -3
473K
∑_{k=1}^{n} k = n(n+1)/2
416K