Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 5 9 ; 0 6 | = 30
276K
F = ma
det| 10 2 ; 1 11 | = 108
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∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
153K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
473K