Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:58Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 4 ; 4 8 | = 40
479K
3β² + 6β + 2 = 0
det| 5 2 ; 3 6 | = 24
276K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 7 6 ; 1 8 | = 50
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 6 ; 7 6 | = -12
153K
1x² + 5x + 7 = 0
det| 4 8 ; 1 5 | = 12
∇²ψ = 0