Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:34Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
6φ² + 8φ + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
63K
∂φ/∂φ = 1φ
det| 4 4 ; 5 5 | = 0
366K
det| 9 4 ; 1 10 | = 86
201K
det| 7 6 ; 1 8 | = 50
176K
∑_{k=1}^{n} k = n(n+1)/2
319K
CH₄ + 2O₂ → CO₂ + 2H₂O
359K