Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:20Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
8β² + 2β + 0 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
390K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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∑_{k=1}^{n} k = n(n+1)/2
416K