Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:48Z
2ψ² + 5ψ + 4 = 0
det| 6 6 ; 3 7 | = 24
75K
det| 5 6 ; 2 6 | = 18
479K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 8 ; 3 5 | = -4
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∇²z = 0
det| 9 4 ; 1 10 | = 86
153K
N₂ + 3H₂ ⇌ 2NH₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8t² + 2t + 3 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1