Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:25Z
E = mc²
det| 1 4 ; 0 2 | = 2
198K
det| 10 7 ; 4 11 | = 82
∑_{k=1}^{n} k = n(n+1)/2
155K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
366K
4θ² + 9θ + 6 = 0
det| 1 4 ; 3 2 | = -10
176K
det| 8 5 ; 5 9 | = 47
det| 9 4 ; 1 10 | = 86
359K
det| 4 4 ; 5 5 | = 0
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
233K
d/dx [x^12] = 12x^11