Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 4 ; 4 8 | = 40
479K
7x² + 6x + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
5β² + 9β + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
473K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
338K
∇²β = 0