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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 00:14Z

12r² + 5r + 0 = 0
ops_6507.dat
∇²β = 0
326K
ops_1832.mol
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
198K
iħ ∂ψ/∂t = Ĥψ
ops_2727.dat
11r² + 2r + 4 = 0
155K
eq_4588.dat
8ψ² + 7ψ + 0 = 0
63K
11x² + 6x + 2 = 0
eq_3539.csv
det| 12 7 ; 7 13 | = 107
366K
eq_8496.eqn
ΔS ≥ 0
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
spec_4870.json
∑_{k=1}^{n} k = n(n+1)/2
176K
eq_9380.mol
ΔS ≥ 0
319K
2H₂ + O₂ → 2H₂O
eq_5781.mol
12x² + 9x + 3 = 0
359K
eq_7087.eqn
det| 3 9 ; 1 4 | = 3
263K
eq_9424.tex
4z² + 4z + 1 = 0
233K
mat_6544.json
ω = 2πf
412K
rxn_8946.dat
∇²z = 0
190K
eq_9083.csv
\oint_C \vec{F}\cdot d\vec{r} = 0
461K
mat_2625.mol
F = G m₁m₂ / r²
246K
rxn_7158.json
1β² + 1β + 7 = 0
439K
rxn_3390.dat
∫₀^∞ e^(-β²) dβ = √π / 2
91K
ops_0667.eqn
\binom{n}{k} = \frac{n!}{k!(n-k)!}
314K
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