Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:46Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
75K
12β² + 9β + 3 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∂z/∂n = 8z
e^{i\pi} + 1 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
1K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
153K