Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 13:27Z
2α² + 5α + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
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iħ ∂ψ/∂t = Ĥψ
CH₄ + 2O₂ → CO₂ + 2H₂O
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9φ² + 5φ + 2 = 0
d/dω [ω^2] = 2ω^1
∫₀^∞ e^(-x²) dx = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
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CH₄ + 2O₂ → CO₂ + 2H₂O
det| 7 4 ; 4 8 | = 40
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